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(This might be an FAQ.) What is the portable way, if any, to
define a function unsigned abs( int ) that returns the correct value especially also for INT_MIN? »Portable« includes that it works both with two's-complement and with one's-complement representation and with any ranges of int and unsigned permitted by C. |
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ram@zedat.fu-berlin.de (Stefan Ram) writes:
> (This might be an FAQ.) What is the portable way, if any, to > define a function > > unsigned abs( int ) > > that returns the correct value especially also for INT_MIN? > »Portable« includes that it works both with two's-complement > and with one's-complement representation and with any ranges > of int and unsigned permitted by C. C allows and implementation in which UINT_MAX == INT_MAX and where, simultaneously, -INT_MAX > INT_MIN (indeed such implementations exist). As a result, the mathematical value of abs(INT_MIN) need not be representable as an unsigned int. I don't think an entirely portable, correct function exists with the given prototype. -- Ben. |
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ram@zedat.fu-berlin.de (Stefan Ram) writes:
> (This might be an FAQ.) What is the portable way, if any, to > define a function > > unsigned abs( int ) > > that returns the correct value especially also for INT_MIN? > >>Portable<< includes that it works both with two's-complement > and with one's-complement representation and with any ranges > of int and unsigned permitted by C. unsigned unsigned_abs( int n ){ return n >= 0 ? n : -(n+1) + 1UL; } Note that for implementations where UINT_MAX == INT_MAX, and where INT_MIN == -INT_MAX - 1 (which must be two's complement), there is no unsigned int value that's right. Under these conditions, unsigned_abs( INT_MIN ) gives zero. In all other cases it gives the right value. (Am I confused or is abs() the name of a standard library function?) |
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Tim Rentsch <txr@alumni.caltech.edu> writes:
>unsigned >unsigned_abs( int n ){ > return n >= 0 ? n : -(n+1) + 1UL; >} >Note that for implementations where UINT_MAX == INT_MAX, >and where INT_MIN == -INT_MAX - 1 (which must be two's >complement), there is no unsigned int value that's right. >Under these conditions, unsigned_abs( INT_MIN ) gives zero. >In all other cases it gives the right value. I was asking because some implementations of »itoa« start with something like: if( n < 0 ){ n = -n; *p++ = '-'; } , but then seem to fail sometimes for INT_MIN. I was wondering whether there is a portable implementation that will be correct for all int values. One could set a flag when n == INT_MIN and then convert (n+1). Eventually one would do the »+1« on the string buffer, possibly with a carry value. >(Am I confused or is abs() the name of a standard library >function?) Well, let's say that, er, I was thinking of a freestanding implementation. |
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On 7/1/2012 2:27 PM, Stefan Ram wrote:
> Tim Rentsch <txr@alumni.caltech.edu> writes: >> unsigned >> unsigned_abs( int n ){ >> return n >= 0 ? n : -(n+1) + 1UL; >> } >> Note that for implementations where UINT_MAX == INT_MAX, >> and where INT_MIN == -INT_MAX - 1 (which must be two's >> complement), there is no unsigned int value that's right. >> Under these conditions, unsigned_abs( INT_MIN ) gives zero. >> In all other cases it gives the right value. > > I was asking because some implementations of »itoa« start > with something like: > > if( n < 0 ){ n = -n; *p++ = '-'; } > > , but then seem to fail sometimes for INT_MIN. > > I was wondering whether there is a portable implementation > that will be correct for all int values. PJ Plauger's "The Standard C Library" shows one way to handle the task, in the underpinnings of printf() et al. Basically, he converts a negative value to `unsigned long', negates that value in `unsigned long' arithmetic, and uses the result to produce the leading digit. Then he strips the leading digit from the value being converted (without the leading digit it must be >LONG_MIN) and proceeds straightforwardly through any remaining digits. Another way would be to start with something like if (n > 0) n = -n; else *p++ = '-'; .... and work in negative numbers all the way. This is a little trickier in C90 than in C99/C11, because in the former `-13 % 10' could be -3 or +7, while in the later Standards it is always -3. -- Eric Sosman esosman@ieee-dot-org.invalid |
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Stefan Ram wrote:
> I was asking because some implementations of »itoa« start > with something like: > > if( n < 0 ){ n = -n; *p++ = '-'; } > > , but then seem to fail sometimes for INT_MIN. > > I was wondering whether there is a portable implementation > that will be correct for all int values. > > One could set a flag when n == INT_MIN and then > convert (n+1). Eventually one would do the »+1« > on the string buffer, possibly with a carry value. #include <limits.h> void itoa(int n, char *s) { int tenth, min_offset; char *p, swap; min_offset = 0; if (0 > n) { if (-INT_MAX > n) { ++n; ++min_offset; } n = -n; *s++ = '-'; } p = s; tenth = n; do { tenth /= 10; *p++ = (char)(n - 10 * tenth + '0'); } while ((n = tenth) != 0); *s = (char)(*s + min_offset); *p = '\0'; while (--p > s) { swap = *s; *s++ = *p; *p = swap; } } -- pete |
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Stefan Ram wrote:
> I was asking because some implementations of »itoa« start > with something like: > > if( n < 0 ){ n = -n; *p++ = '-'; } > > , but then seem to fail sometimes for INT_MIN. > > I was wondering whether there is a portable implementation > that will be correct for all int values. void itoa(int n, char *s) { if (0 > n) { *s++ = '-'; *utoa_plus_one(-(n + 1), s) = '\0'; } else { *utoa_plus_zero(n, s) = '\0'; } } static char * utoa_plus_zero(unsigned n, char *s) { unsigned digit, tenth; tenth = n / 10; digit = n - 10 * tenth; if (tenth != 0) { s = utoa_plus_zero(tenth, s); } *s = (char)(digit + '0'); return s + 1; } static char * utoa_plus_one(unsigned n, char *s) { unsigned digit, tenth; tenth = n / 10; digit = n - 10 * tenth; if (digit == 9) { if (tenth != 0) { s = utoa_plus_one(tenth, s); } else { *s++ = '1'; } *s = '0'; } else { if (tenth != 0) { s = utoa_plus_zero(tenth, s); } *s = (char)(digit + '1'); } return s + 1; } -- pete |
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Stefan Ram wrote:
> > Tim Rentsch <txr@alumni.caltech.edu> writes: > >Note that for implementations where UINT_MAX == INT_MAX, > I was asking because some implementations of »itoa« start > with something like: > > if( n < 0 ){ n = -n; *p++ = '-'; } > > , but then seem to fail sometimes for INT_MIN. > > I was wondering whether there is a portable implementation > that will be correct for all int values. > > One could set a flag when n == INT_MIN and then > convert (n+1). the special case is (-INT_MAX > n), rather than (n == INT_MIN), because of the (UINT_MAX == INT_MAX) possibility, which was mentioned by Tim Rentsch. -- pete |
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ram@zedat.fu-berlin.de (Stefan Ram) writes:
> Tim Rentsch <txr@alumni.caltech.edu> writes: >>unsigned >>unsigned_abs( int n ){ >> return n >= 0 ? n : -(n+1) + 1UL; >>} >>Note that for implementations where UINT_MAX == INT_MAX, >>and where INT_MIN == -INT_MAX - 1 (which must be two's >>complement), there is no unsigned int value that's right. >>Under these conditions, unsigned_abs( INT_MIN ) gives zero. >>In all other cases it gives the right value. > > I was asking because some implementations of >>itoa<< start > with something like: > > if( n < 0 ){ n = -n; *p++ = '-'; } > > , but then seem to fail sometimes for INT_MIN. > > I was wondering whether there is a portable implementation > that will be correct for all int values. [snip] void simple_itoa( int n, char *s ){ enum { D = 1 + CHAR_BIT*sizeof(int)/3 }; char buffer[D+1], *p = buffer + D; *p = 0; if( n < 0 ) *s++ = '-'; if( n > 0 ) n = -n; while( n < -9 ){ int r = -(n+10)%10; *--p = '0' + r; n = (n+r)/10; } *--p = '0' + -n; strcpy( s, p ); } 1. Works for all int values. 2. No casting or other types needed (and so no dependencies on ranges of any other types). 3. No checks for "unusual" values. 4. Same results under both C90 and C99 (and C11) semantics. 5. (The expression computing a value for 'D' can be improved, but the one here is probably good enough in most cases.) The code above may be used freely for any purpose subject only to the condition that it not be claimed as original work, ie, by anyone other than me. (And especially not by any patent trolls out there...) |
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