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Old 10-20-2006, 11:08 PM
glen herrmannsfeldt
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Default Re: integral along a hyperbola

oogunlade@hotmail.com <oogunlade@hotmail.com> wrote:
> Hi Thanks, i think i see what you mean, let me see if i get this right,
> my integral int {f(z)dz} becomes int{f(z)ds} i.e int {
> f(x+i*c/x)*sqrt{dx^2[1+c^2/x^4]}, so by simply dividing my x axis to m
> small intervals i get dx, different values of x and then summing up get
> my integral.


I thought of that, but I don't believe it is the usual way
to do complex integration. You can look at:

http://mathworld.wolfram.com/ContourIntegration.html

Depending on the actual problem, you have to decide which
one you need.

-- glen
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